1905 Paris–Roubaix

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1905 Paris–Roubaix
Race details
Dates 23 April
Stages 1
Distance 268 km (166.5 mi)
Winning time 8h 4' 15"
Results
  Winner  Louis Trousselier (FRA)
  Second  René Pottier (FRA)
  Third  Henri Cornet (FRA)
← 1904
1906 →

The 1905 Paris–Roubaix was the tenth edition of the Paris–Roubaix, a classic one-day cycle race in France. The single day event was held on 23 April 1905 and stretched 268 km (167 mi) from Paris to its end in a velodrome in Roubaix.[1] The winner was Louis Trousselier from France.[2]

Results[edit]

Final results (1–10)[2]
Rank Cyclist Time
1  Louis Trousselier (FRA) 8h 4' 15″
2  René Pottier (FRA) +7' 00″
3  Henri Cornet (FRA) +16' 00″
4  Hippolyte Aucouturier (FRA) +23' 00″
5  Edouard Wattelier (FRA) +48' 00″
6  Claude Chapperon (FRA) +57' 00″
7  Alois Catteau (BEL) +1hr 6' 00″
8  Paul Chauvet (FRA) +1hr 12' 00″
9  Lazare Brault (FRA) +1hr 20' 00″
10  Louis Colsaet (FRA) +1hr 20' 01″

References[edit]

  1. ^ "10th Paris – Roubaix, 1905". bikeraceinfo. Retrieved 27 February 2015.
  2. ^ a b "1905 » 10th Paris – Roubaix". ProCyclingStats. Retrieved 27 February 2015.