Leskov Island (Antarctica)

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Leskov Island
Leskov Island is located in Antarctica
Leskov Island
Leskov Island
Location in Antarctica
Geography
Location Antarctica
Coordinates 66°36′S 85°10′E / 66.600°S 85.167°E / -66.600; 85.167Coordinates: 66°36′S 85°10′E / 66.600°S 85.167°E / -66.600; 85.167
Area 49.5 km2 (19.1 sq mi)
Length 9 km (5.6 mi)
Width 5.5 km (3.42 mi)
Highest elevation 185 m (607 ft)
Administration
Administered under the Antarctic Treaty System
Demographics
Population Uninhabited

Leskov Island is an ice-covered island in the West Ice Shelf of Antarctica, rising to 185 metres (600 ft), 11 kilometres (6 nmi) northwest of Mikhaylov Island. It was discovered by the Soviet expedition of 1956, who named it for Lieutenant A. Leskov of the sloop Vostok on the Bellingshausen expedition of 1819–21.[1]

References[edit]

  1. ^ "Leskov Island". Geographic Names Information System. United States Geological Survey. Retrieved 2013-06-11.

 This article incorporates public domain material from the United States Geological Survey document "Leskov Island" (content from the Geographic Names Information System).