1892 United States House of Representatives elections
The 1892 United States House of Representatives elections were held for the most part on November 8, 1892, with Oregon, Maine, and Vermont holding theirs early in either June or September. They coincided with the election of Grover Cleveland as president for the second, non-continuous, time, defeating incumbent Benjamin Harrison. Elections were held for 356 seats of the United States House of Representatives, representing 44 states, to serve in the 53rd United States Congress. They were the first elections after reapportionment following the 1890 United States census, increasing the size of the House. Special elections were also held throughout the year.
Image: Charles Frederick Crisp (cropped)
Image: TB Reed
1890 United States House of Representatives elections
The 1890 United States House of Representatives elections were held for the most part on November 4, 1890, with five states holding theirs early in between June and October. They occurred in the middle of President Benjamin Harrison's term. Elections were held for 332 seats of the United States House of Representatives, representing 44 states, to serve in the 52nd United States Congress. Special elections were also held throughout the year.
Image: Charles Frederick Crisp (cropped)
Image: TB Reed
Image: Jerry Simpson (cropped)